the image of the parabola `y^2=x` in the line `x+y+4=0` is

The mirror image of the parabola y^2=4x in the tangent to the parabola at the point (1, 2) is (a) (x-1)^2=4(y+1) (b) (x+1)^2=4(y+1) (c) (x+1)^2=4(y-1) (d) (x-1)^2=4(y-1)

Tangents are drawn to the parabola y^2=4x at the point P which is the upper end of latusrectum . Image of the parabola y^2=4x in the tangent line at the point P is

The are bounded by the parabola y^(2)=4ax and the line x = a and x = 4a is...

Find the area bounded by the parabola y=x^2 and the lines y=0 and y=4

The mirror image of the parabola y^(2)=4x in the tangent to the parabola at the point (1,2) is (a)(x-1)^(2)=4(y+1)(b)(x+1)^(2)=4(y+1)(c)(x+1)^(2)=4(y-1) (d) (x-1)^(2)=4(y-1)

Find the image of the line x-y-1=0 in the line 2x-3y+1=0 .

Let the curve C be the mirror image of the parabola y^2 = 4x with respect to the line x+y+4=0 . If A and B are the points of intersection of C with the line y=-5 , then the distance between A and B is

Let the curve C be the mirror image of the parabola y^(2)=4x with respect to the line x+y+4=0. If A and B are the points of intersection of C with the line y=-5, then the distance between A and B is