the equation of a plane through the line of intersection the planes `x+2y=3,y-2z+1=0` and perpendicular to the first plane is:

The equation of plane through the line of intersection of the planes 2x+3y+4z-7=0,x+y+z-1=0 and perpendicular to the plane x+y+z-1=0

Find the equation of the plane passing through the line of intersection of the planes 2x-y=0,3z-y=0 and perpendicular to the plane 4x+5y-3z=8

Find the equation of the plane through the line of intersection of the planes x+2y+3z+2=0 , 2x+3y-z+3=0 and perpendicular to the plane x+y+z=0

Find the equation of the plane through the line of intersection of the planes 3x-y+z-1=0, 2x+y+3z-7=0 and perpendicular to the plane x-5y+3z=2 .

The equation of the plane through the line of intersection of the planes x+y+z-1=0, 2x+3y+4z-5=0 and perpendicular to the plane is x+y+z=0 is

Find the equation of the plane through the line of intersection of the planes: x+3y-z+1=0 and x+y-2z+3=0 and perpendicular to the plane 3x-y-2z-4=0

The equation of the plane through the line of intersection of the planes 2x+y-z+5=0 and x+2y+3z=4 and perpendicular to the plane 5x+3y+6z=10 is -