The amount of energy released when `10^(12)` atoms of `Cl` vapours are converted to `Cl^(ɵ)` ions, according to the equation :
`C_((g))+e^(-) rarr Cl_((g))^(ɵ)` is `58 xx 10^(-10)J`
Calculate the `Delta_(eg)H^(ɵ)` of `Cl` atom in `kJ mol^(-1)` and `eV "atom"^(-1)`.

The amount of energy released when 1 xx10^10 atoms of chlorine in vapour state are converted to Cl^(–1) ions according to the equation, Cl(g) + e^(-) to Cl^(-) (g) " is " 57.86 xx 10^(-10) J Calculate the electron gain enthalpy of chlorine atom in terms of kJ "mol"^(–1 ) and eV per atom.

The amount of energy when millon atoms of iodine are completely converted into I^(-) ions in the vapour state according to the equation, I(g) +e^(-)(g) rarr I^(-)(g) is 5.0 xx 10^(-13)J .

The amount of energy when million atoms of iodine are completely converted into I^(-) ions in the vapour state according to the equation, I(g) +e^(-)(g) rarr I^(-)(g) is 5.0 xx 10^(-13)J .

The amount of energy when million atoms of iodine are completely converted into I^(-) ions in the vapour state according to the equation, I_((g))+e^(-) to I^(-)_((g)) is 4.9X10^(-13) J.What would be the electron gain enthalpy of iodine in terms of KJ mol^(-1) and eV per atom?

the amount of energy released when 10^(6) atoms of iodine in vapour state are converted to I^(-) ions is 4.8 xx 10^(-13) J . What is the electron affinity of iodine in ev/atom.