Circle K is inscribed in the first quadrant touching the circle radius of the circle K, is-

A circle touches the lines y=(x)/(sqrt(3)),y=x sqrt(3) and unit radius.If the centre of this circle lies in the first quadrant then possible equation of this circle is

In a circle of radius R a square is inscribed, then a circle is inscribed in the square,a new square in the circle and so on for n xx.If the ratio of the limit of the sum of areas of all the circles to the limit of the sum of areas of all the squares as n rarr oo is k, then find the value of (4k)/(pi) .

A circle of radius 2 units lies in the first qudrant touching both the axes. Then the equation of the circle with centre (6,5) and touching the above circle externally is

A square is inscribed in circle of radius R, a circle is inscribed in the square, a new square in the circle and so on for n times. Sum of the areas of all circles is

A square is inscribed in circle of radius R, a circle is inscribed in the square, a new square in the circle and so on for n times. Sum of the areas of all circles is

In the given figure, PQR is a quadrant whose radius is 7 cm. A circle is inscribed in the quadrant as shown in the figure. What is the area (in cm^(2) ) of the circle

The radius of the larger circle lying in the first quadrant and touching the line 4x+3y-12=0 and the coordinate axes, is

The radius of the larger circle lying in the first quadrant and touching the line 4x+3y-12=0 and the coordinate axes, is

The radius of the larger circle lying in the first quadrant and touching the line 4x+3y-12=0 and the coordinate axes, is