Let equation of two sides of a triangle are `4x+5y=20` and `3x-2y+6=0` If orthocentre of triangle is `(1,1)` then the equation of third side of triangle is (a) `y+10=(-13)/61(x+35/2)` (2) `y+10=(-13)/61(x-35/2)` (3) `y+10=13/61(x-35/2)` (4) `y-10=13/61(x-35/2)`