[CLASS 10 BOARDS 2019] The following table gives the number of participants in a yoga camp: `[("Age in years", 20-30, 30-40, 40-50, 50-60, 60-70),("No. of Participants", 8,40,58,90,83)]`. Find the modal age of the participants.

The following table gives the marks scored by 100 students in an entrance examination. Marks:, 0-10, 10-20, 20-30, 30-40, 40-50, 50-60, 60-70, 70-80 No. of Students (Frequency):, 4, 10, 16, 22, 20, 18, 8, 2

For the following data the value of Q_(1) + Q_(3) - Q_(2), is {:("Age in years" ,:,20,30,40,50,60,70,80),("No. of members" ,:,3,61,132,153,140,51,3):}

The modal class for the following frequency distribution, is {:("Marks:", 0-10,10-20,20-40,40-50,50-60,60-70,70-90,90-100),("No. of students:",4,6,14,16,14,8,16,5):}

The following table gives distributionn of marks secured by some stidents : {:("Wege Rate (Rs.)",10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Number of Students"," "42," "38," "120," "84," "48," "36," "31):} Calculate the median marks secured by the students.

Find out median , with the help of the following data : {:("Price Level",10-20,20-30,30-40,40-50,50-60,60-70),("Number of Commodity"," "2," "5," "8," "4," "6," "3):}

Estimate the mode of the following data from the histogram. {:("Class Interval",0-10,10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Frequency",8,10,15,16,20,13,14,12):}

Average age of the people of a counry is shown in the following table: {:("Age (Years)",10-20,20-30,30-40,40-50,50-60),("People ('000)"," "30," "32," "15," "12," "9):} Find out mean age by Direct Method.

Find the mean deviation about the mean for the following data: Marks obtained,10-20,20 - 30,30-40,40-50,50-60,60-70,70-80 Number of students,2,3,8,14,8,3,2