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Minimum distance between the curves y^2=...

Minimum distance between the curves `y^2=4x and x^2+y^2-12x+31=0` is

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`(beta^2/4,beta)` point on the padoda
`2*(dy)/(dx)*y=4`
`(dy)/(dx)=2/y=2/beta`
`(beta-0)/((beta^2/4)-6)*2/beta=-1`
`8/(beta^2-24)=-1`
`sqrt((beta^2/4-6)^2+beta^2)-sqrt5`
`sqrt((16/4-6)^2+16)-sqrt5`
`sqrt(4+16)-sqrt5=2sqrt5-sqrt5=sqrt5`
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