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[" If "20C_(1)+(2^(2))^(20)C_(2)+(3^(2))^(20)C_(3)+.........+(20^(2))^(20)C_(20)],[=A(2^(8))," then the ordered pair "(A,beta)" is equal "],[" to ":-],[[" (1) "(420,18)," (2) "(380,19)],[" (3) "(380,18)," (4) "(420,19)]]

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If .^(20)C_(1)+(2^(2)) .^(20)C_(2) + (3^(2)).^(20)C_(3) +......+(20^(2)).^(20)C_(20)=A(2^(beta)) , then the ordered pair (A, beta) is equal to

If .^(20)C_(1)+(2^(2)) .^(20)C_(2) + (3^(2)).^(20)C_(3) +......+(20^(2)).^(20)C_(20)=A(2^(beta)) , then the ordered pair (A, beta) is equal to

1.^(20)C_(1)-2.^(20)C_(2)+3.^(20)C_(3)-...-20.^(20)C_(20)

The value of 1^(1).^(20)C_(1)+2^(2).^(20)C_(2)+3^(2).^(20)C_(3)+….+(20)^(2).^(20)C_(20) is

The sum of the series 20C_(0)-^(20)C_(1)+^(20)C_(2)-^(20)C_(3)+...-...+^(20)C_(10) is:

if 3^(1)20C_(0)+(3^(2))/(2)20C_(1)+(3^(3))/(3)20C_(2)+............ upto 21 terms =(2^(a)-1)/(b) then the the value of (b)/(a) equal to :

""^(20)C_(0)-(""^(20)C_(1))/(2)+(""^(20)C_(2))/(3)-(""^(20)C_(3))/(4)+....

(C_(1))/(C_(0))+(2.C_(2))/(C_(1))+(3.C_(3))/(C_(2))+ . . .+(20.C_(20))/(C_(19))=