[" The equation Im "((iz-2)/(z-i))+1=0,z in C,z!=" irepresents a part of a "],[" circle having radius equal to "]

The equation I m((i z-2)/(z-i))+1=0, z & epsi; C , z!=i represents a part of a circle having radius equal to

The equation Im((iz-2)/(z-i))+1=0,z& varepsilon;C,z!=i represents a part of a circle having radius equalto.4

The equation Z^(3)+iZ-1=0 has

The equation Z^(3)+iZ-1=0 has

If Im((iz+2)/(z+i))=-1 represents part of a circle with radius r units, then the value of 4r^(2) is (where, z in C, z ne i,lm(z) represents the imaginary part of z and i^(2)=-1 )

If Im((iz+2)/(z+i))=-1 represents part of a circle with radius r units, then the value of 4r^(2) is (where, z in C, z ne i,lm(z) represents the imaginary part of z and i^(2)=-1 )

if Im((z+2i)/(z+2))= 0 then z lies on the curve :

if Im((z+2i)/(z+2))= 0 then z lies on the curve :

Im ((2z+1)/(iz+1))=5 represents