In Young's double slit experiment, the 8th maximum with wavelength `lambda_1` is at a distance `d_1` from the central maximum and the 6th maximum with a wavelength `lambda_2` is at a distance `d_2`. Then `(d_1//d_2)` is equal to

In Young's double slit experiment, the 10^(th) maximum of wavelength lambda_(1) is at a distance y_(1) from its central maximum and the 5^(th) maximum of wavelength lambda_(2) is at a distance y_(2) from its central maximum. The ratio y_(1)//y_(2) will be

In Young's double slit experiment, the 10^(th) maximum of wavelength lambda_(1) is at a distance y_(1) from its central maximum and the 5^(th) maximum of wavelength lambda_(2) is at a distance y_(2) from its central maximum. The ratio y_(1)//y_(2) will be

In Young's double slit experiment the 7th maximum with wavelength lambda_(1) is at a distance d_(1) , and that with wavelength lambda_(2) is at distance d_(2) . Then d_(1)//d_(2) is

In Young's double slit experiment the 7th maximum with wavelength lambda_(1) is at a distance d_(1) , and that with wavelength lambda_(2) is at distance d_(2) . Then d_(1)//d_(2) is

In Youngs double slit experiment the 7th maximum with wavelength lambda_1 is at a distance d_1 and that with wavelength lambda_2 is at distance d_2 . Then d_1//d_2=

In Young's double slit experiment, the 10th maximum of wavelength lambda_(1) is at distance of y_(1) from the central maximum. When the wavelength of the source is changed to lambda_(2) , 5th maximum is at a distance of y_(2) from its central masximum. Then (y_(1))/(y_(2)) is