Consider the plane `(x,y,z)= (0,1,1) + lamda(1,-1,1)+mu(2,-1,0)` The distance of this plane from the origin is

Find the distance of the plane 2x-y+2z+1=0 from the origin.

Find the distance of the plane 2x-y-2z+1=0 from the origin.

A plane passes through (1,1,1). It is perpendicular to the line (x-1)/(3)= (y-1)/(0) - (z-1)/(4) Then the distance of this plane from the origin is............

Write the distance of the plane 2x-y+2z+1=0 from the origin.

Write the distance of the following plane from the origin: 2x-y+2z+1=0

Write the distance of the following plane from the origin: 2x-y+2z+1=0

If the distance of the plane x - y + z + lambda = 0 from the point (1, 1, 1) is d_1 and the distance of this point from the origin is d_2 and d_2d_2 = 5 then find the value of lambda .

A plane passes through (1, - 2, 1) and is perpendicular to the planes 2x - 2y +z = 0 and x-y + 2z = 4. The distance of the plane from the point (1, 2, 2) is:

If the projection of the line (x)/(2)=(y-1)/(2)=(z-1)/(1) on a plane P is (x)/(1)=(y-1)/(1)=(z-1)/(-1) Then the distance of plane P from origin is