Distance between the slit shown in figure is `d = 20 lambda`, where `lambda` is the wavelength of light used. Find the angle `theta` where
a. central maxima (where path difference is zero) is obtained, and
b. third-order maxima is obtained.

The maximum intensity in Young’s double slit experiment is I_0 .Distance between the slits is d=2lambda ,where lambda is the wavelength of monochromatic light used in experiment. What will be the intensity of light in front of one of the slits on a screen at a distance D = 6 d?

In the Young's double-slit experiment, the intensity of light at a point on the screen where the path difference is lambda is K, ( lambda being the wavelength of light used). The intensity at a point where the path difference is lambda//4 will be

In the Young's double-slit experiment,the intensity of light at a point on the screen where the path difference is lambda is K ( lambda being the wave length of light used).The intensity at a point where the path difference is lambda/4 , will be

In the Young's double slit experiment, the intensity of light at a point on the screen where the path difference is lambda is K, ( lambda being the wave length of light used). The intensity at a point where the path difference is lambda"/"4 , will be

In the young,s double -slit experiment ,the intensity of light at a point on the screen where the path difference is lambda is K, (lambda being the wavelenght of light used). The intersity at a point where the path difference is lambda//4 , will be

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is 5000nm . The distance of 100^(th) maxima from the central maxima is: