shows the variation in the internal energy U with the volume V of 2.0 mol of an ideal gas in a cyclic process abcda. The temperatures of the gas at b and c are 500 K and 300 K respectively. Calculate the heat absorbed by the gas during the process.

Fig. shows the variation of internal energy (U) with the pressure (P) of 2.0 mole gas in cycle process abcda . The temperatures of gas at c and d are 300 and 500 K , respectively. Calculate the heat absorbed by the gas during the process.

Figure shows the variation of internal energy (U) with the pressure (P) of 2.0 mole gas in cyclic process abcda.The temperature of gas at c and d are 300 and 500 K respectively. The heat absorbed by the gas during the process is Xxx 10 R ln 2 . Find the value of x.

Figure shows the variation of internal energy (U) with the pressure (P) of 2.0 mole gas in cyclic process abcda.The temperature of gas at c and d are 300 and 500 K respectively. The heat absorbed by the gas during the process is Xxx 10 R ln 2 . Find the value of x.

Consider the following cyclic abcda performed on 2 mole of an ideal gas. The temperature of the gas at b and c are 400 k and 300 k respectively. Calculated the heat absorbed by the gas during the process in calories.

One mole of an ideal monoatomic gas undergoes a cyclic process, as shown in the figure. If the temperature of the gas at state 1 is 300 K and at state 4 is 500 K, then heat exchanged during process 2rarr3 , is

One mole of an ideal monoatomic gas undergoes a cyclic process, as shown in the figure. If the temperature of the gas at state 1 is 300 K and at state 4 is 500 K, then heat exchanged during process 2rarr3 , is

One mole of an ideal gas is taken through a cyclic process. The minimum temperature during the cycle is 300K. Then, net exchange of heat for complete cycle is