A body of mass 2 kg moving on a horiontal surface with apeed `v_(i)=1ms^(-1)` enters a rough patch ranging from `x=0.5m` to `x=1.5m.` If the body comes to rest after pussing the patch, then find the retarding force on the body.

A body of mass 2 kg moving on a horiontal surface with speed v_(i)=1ms^(-1) enters a rough patch ranging from x=0.5m to x=1.5m. If the body comes to rest after passing the patch, then find the retarding force on the body.

A body of mass 2 kg moving on a horizontal surface with a speed v_(i)=1ms^(-1) enters a rough patch ranging from x=0.5m to x=1.5m. If the body comes to rest after passing the patch, then find the retarding force on the body.

A block of mass m=1kg moving on a horizontal surface with speed v_(i)=2ms^(-1) enters a rough patch ranging from x0.10m to x=2.01m . The retarding force F_(r) on the block in this range ins inversely proportional to x over this range F_(r)=-(k)/(x) fo r 0.1 lt xlt 2.01m =0 for lt 0.1m and x gt 2.01m where k=0.5J . What is the final K.E. and speed v_(f) of the block as it crosses the patch?

A block of mass m=1kg moving on a horizontal surface with speed v_(i)=2ms^(-1) enters a rough patch ranging from x0.10m to x=2.01m . The retarding force F_(r) on the block in this range ins inversely proportional to x over this range F_(r)=-(k)/(x) fo r 0.1 lt xlt 2.01m =0 for lt 0.1m and x gt 2.01m where k=0.5J . What is the final K.E. and speed v_(f) of the block as it crosses the patch?

A block of mass m= 1 kg , moving on a horizontal surface with speed v_(t)= 2 ms^(-1) enters a rough patch ranging from x= 0.10m" to "x= 2.01m . The retarding force F_(r ) on the block in this range is inversely proportional to x over this range, F_(r )= (-k)/(x)" for "0.1 lt x lt 2.01m = 0 " for "x lt 0.1m" and "x gt 2.01m where k= 0.5 J . What is the final kinetic energy and speed v_(f) of the block as it crosses this patch?