The equilibrium constant of a reaction is `1xx10^(20)` at `300 K`. The standard free energy change for this reaction is :

The equilibrium constant foa a reaction is 1 xx 10^(20) at 300 K.Find the standard free energy vhange for this reaction.

The equilibrium constant of a reaction is 0.008 at 298 K . The standard free energy change of the reaction at the same temperture is

The equilibrium constant of a reaction is 0.008 at 298 K. The standard free energy change of the reaction at the same temperature is :

The equilibrium constant of a reaction is 0.008 at 298 K. The standard free energy change of the reaction at the same temperature is

If the equilibrium constant of a reaction is 2×10^3 at 25°C then the standard Gibbs free energy change for the reaction will be

If the equilibrium constant of a reaction is 2×10^3 at 25°C then the standard Gibbs free energy change for the reaction will be

At 300 K, the equilibrium constant for a reaction is 10. the standard free energy change (in kJ mol^(-1) ) for the reaction is

The equilibrium constant for the reaction given below is 2.0xx10^(-7) at 300K. Calculate the standard free energy change for the reaction, PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) . Also, calculate the standard entropy change if DeltaH^@=28.40kJmol^(-1) .