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A line bisecting the ordinate PN of a po...

A line bisecting the ordinate PN of a point P`(at^2,2at)`,t>0, on parabola `y^2 = 4ax` is drawn parallel to the axis to meet curve at Q. If NO meets meets the tangent at the vertex at Point T. Then the coordinates of T are:

Text Solution

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`a^2t^2=4ax`
`x=(at^2)/4`
`tantheta=(k*at)/(at^2/4)=(at)/(3at^2/4)`
`k*at=(at)/3`
`k=4at/3`
option a is correct.
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