Two balls are thrown simultaneously, A vetically upwards with a speed of `20 ms^(-1)` from the ground, and B vetically downwards from height of 40 m with the same speed and along the same line of motion. At what points do the two balls collide? Take `g= 9.8 ms^(-2)`.

Two balls are thrown simultaneously, A vertically upwards with a speed of 20 m/s from the ground, and B vertically downwards from a height of 40 m with the same speed along the same line of motion. At what point do the two balls collide? Take g = 9.8 m//s^(2) .

Two balls are thrown simultaneously, A vertically upwards with a speed of 20 m/s from the ground, and B vertically downwards from a height of 40 m with the same speed along the same line of motion. At what point do the two balls collide? Take g = 9.8 m//s^(2) .

A ball 'A' is thrown upwards from ground level with a velocity of 20 ms^(-1) . Another ball 'B' is thrown downwards from a height of 40 m with the same speed. Find the height at which the two balls meet (take g = 10 m s^(-2) ).

A ball is thrown vertically upwards with a speed of 9.8 m/s from the ground. Draw the x-t, v-t and a-t graph for its motion.

A ball thrown vertically upwards with a speed of 19.6ms^(-1) from the top of a tower returns to the Earth in 6s. Find the height of the tower. (g=9.8m//s^(2))

Two balls of different masses are thrown vertically upwards with the same speed . They pass through the point of projection in their downward motion with the same speed ( Neglect air resistance ).

Two balls of different masses are thrown vertically upwards with the same speed . They pass through the point of projection in their downward motion with the same speed ( Neglect air resistance ).

A ball is thrown vertically upwards with a speed of 10 ms^-1 from the top of a tower 200 m high and another is throwtl .vertically downwards with the same speed simultaneously. The time difference between them in reaching the ground, in second, if g is taken as 10 ms^-2 , is