m balls are distributed among a boys and b girls. Prove that the probability that odd numbers of balls are distributed to boys is `((b+a)^m - (b+a)^m)/ (2 (a+b)^m)`.

Answer the following questions : If m things are distributed among a men and women, show that the probability of receiving odd number of things by 'men is 1/2[((b+a)^m - (b-a)^m)/(b+a)^m] .

If m things are distributed among a men and b women. Then the probability that number of things received by men is odd is

If m things are distributed among a men and b women. Then the probability that number of things received by men is odd is

If n toys are distributed among N boys randomly, then the probability that a particular boy gets r(lt n) toys is

If m things are distributed among a men and b women, then show that the chances that the number of things received by men is odd are given by ((b+a)^(m)-(b-a)^(m))/(2(b+a)^(m))

If m things are distributed among a men and b women, then show that the chances that the number of things received by men is odd are given by ((b+a)^(m)-(b-a)^(m))/(2(b+a)^(m))

180 oranges are distributed among 70 boys and girls such that each boy gets 2 and each girl gets 3 oranges.The number of boys are (a) 25 (b) 30 (c) 40 (d) 70