Let `veca, vecb, vecc` be three vectors such that `a!=0` and `veca xx vecb = 2veca xx vecc, |veca| = |vecc| = 1, |vecb| = 4` and `|vecb xx vecc| = sqrt15.` If `vecb-2 vecc = lambda veca,` then `lambda` is

Let veca,vecb,vecc be three vectors such that veca ne vec0 and veca xx vecb=2veca xx vecc, |veca|=|vecc|=1,|vecb|=4 and |vecbxxvecc|=sqrt(15) . If vecb-2vecc=lambdaveca , then |lambda| is equal to :

If three vectors veca, vecb,vecc are such that veca ne 0 and veca xx vecb = 2(veca xx vecc),|veca|=|vecc|=1, |vecb|=4 and the angle between vecb and vecc is cos^(-1)(1//4) , then vecb-2vecc= lambda veca where lambda is equal to:

If three vectors veca, vecb,vecc are such that veca ne 0 and veca xx vecb = 2(veca xx vecc),|veca|=|vecc|=1, |vecb|=4 and the angle between vecb and vecc is cos^(-1)(1//4) , then vecb-2vecc= lambda veca where lambda is equal to:

If veca, vecb, vecc are the unit vectors such that veca + 2vecb + 2vecc=0 , then |veca xx vecc| is equal to:

If veca , vecb and vecc are three vectors such that vecaxx vecb =vecc, vecb xx vecc= veca, vecc xx veca =vecb then prove that |veca|= |vecb|=|vecc|

If veca , vecb and vecc are three vectors such that vecaxx vecb =vecc, vecb xx vecc= veca, vecc xx veca =vecb then prove that |veca|= |vecb|=|vecc|

If veca , vecb and vecc are three vectors such that vecaxx vecb =vecc, vecb xx vecc= veca, vecc xx veca =vecb then prove that |veca|= |vecb|=|vecc|

If veca , vecb and vecc are three vectors such that vecaxx vecb =vecc, vecb xx vecc= veca, vecc xx veca =vecb then prove that |veca|= |vecb|=|vecc|

If veca, vecb and vecc are vectors such that veca. vecb = veca.vecc, veca xx vecb = veca xx vecc, a ne 0. then show that vecb = vecc.