Mean of 5 observations is 7. If four of these observations are `6,7,8,10` and one is missing then the variance of all the five observations is

Mean of 5observations is 7. If four of these observations are 6,7,8,10 and one is missing then the variance of all the five observations is

Mean of 5 observation is 7. if four of these observation are 6,7,8,10 and one is missing, then te variance of all the five observations is

Mean of 5 observation is 7. if four of these observation are 6,7,8,10 and one is missing, then te variance of all the five observations is

The mean and variance of 7 observations are 8 and 16 respectively. If two observations are 6 and 8, then the variance of the remaining 5 observations is :

The mean and variance of the 7 observations is 8 and 12 resp. . If two observations are 8 and 6 . find the variance of the remaining observation

Suppose arithmetic mean of "10" observations is "10" and variance is "40." Further let arithmetic mean and variance of "6" observations from these "10 observations be "6" and "20" respectively.Then the variance of remaining observations is

The variance of 50 observations is 7. If each observation is multiplied by 6 and then 5 is subtracted from it, then the variance of the new data is

The mean of five observations is 4 and their variance is 5.2. If three of these observations are 2, 4 and 6, then the other two observations are :

The mean of five observations is 4 and their variance is 5.2. If three of these observations are 2, 4 and 6, then the other two observations are :

The mean of five observations is 4 and their variance is 5.2. If three of these observations are 2, 4 and 6, then the other two observations are