A ball is thrown at an angle `theta` with the horizontal and the range is maximum. The value of `tantheta` is:-

A projectile is thrown at an angle theta with the horizontal and its range is R_(1) . It is then thrown at an angle theta with vertical anf the range is R_(2) , then

A projectile is thrown at an angle theta with the horizontal and its range is R_(1) . It is then thrown at an angle theta with vertical anf the range is R_(2) , then

At what angle will the horizontal range be maximum?

A player kicks up a ball at an angle theta to the horizontal. The horizontal range is maximum when theta equals-

A ball is thrown at an angle theta with the horizontal. Its time of flight is 2 s. Its horizontal range is 100 m. What is the horizontal component of velocity of projection ? Take g =10 ms^(-2) .

A stone thrown at an angle to theta with the horizontal reaches a maximum height H. Then the time of flight of stone will be

A stone is thrown at an angle theta to the horizontal reaches a maximum height H. Then the time of flight of stone will be:

A stone is thrown at an angle theta to the horizontal reaches a maximum height H. Then the time of flight of stone will be: