One kg of water at `373K` is converted into steam at the same temperature. The volume `1 cm^(3)` of water becomes `1671 cm^(3)` on boiling. Calculate the change in internal energy of the system , if heat of vaporisation is `540 cal g^(-1)`. Given standard atmospheric pressure `=1.013xx10^(5) Nm^(-2)`.

One gm of water at 373 K is converted into steam at the same temperature. The volume of 1 c .c of water becomes' 1671 c.c on boiling. Calculate the change in internal energy of the system if heat of vaporisation of water is 5.4xx10^5calkg^-1 .

1 g of water at 100^(@)C is converted into steam at the same temperature. If the volume of steam is 1671 cc find the change in internal energy of the system. Latent heat of steam =2256 J g ^(-1).

Calculate the change in internal energy when the 1 g water is converted into steam.

1g of water at 100^(@)C is converted into steam at the same temperature. If the volume of steam is 1671 cm^(3) , find the change in the internal energy of the system. Latent of steam =2256 Jg^(-1) . Given 1 atmospheric pressure = 1.013xx10^(5) Nm^(-2)

1 g of water at 100^@C is coverted into steam at the same temperature. If the volume of steam is 1671 cm^2 , find the change in the internal energy of the system. Latent heat of steam = 2256 Jg ^-1 . (1 atmosphere pressure = 1.013 xx 10^5 Nm^-2 )

The volume of 1 g of water (1 cm^3) becomes 1671 cm^(3) on being converted to steam at standard atmosphere pressure. Find out the work done and rise in internal energy. Given, latent heat of vaporisation of water = 540 cal cdot g^(-1) , the standard atmosphere pressure = 1.013 xx 10^(5) N cdot m^(-2) .

1 g of water (volume 1 cm^(3) becomes 1671 cm^(3) of steam when boiled at a pressure of 1atm. The latent heat of vaporisation is 540 cal/g, then the external work done is (1 atm = 1.013 xx 10^(5) N/ m^(2))