`Cot A Cot B=2, Cos (A+B) = 3/5 => sinA.sin B=` (i)`2/5` (ii)`1/5` (iii)`4/5` (iv)`3/5`

If Cot A Cot B = 2 & Cos (A+B) = 3/5 then Sin A Sin B

cot A cot B=2,cos(A+B)=(3)/(5)rArr sin A sin B=

If cos(A-B)=3/5 and tan A tan B=2, then (a) cos A cos B=1/5 (b) sin A sin B=-2/5 (c) cos A cos B=-1/5 (d) sin A sin B=-1/5

If tan A, tan B are the roots of x^(2)-2x+2=0 then sin^(2)(A+B)=(i)(4)/(5) (ii) (1)/(2)(iii)(3)/(5)(iv)(1)/(4)

If cos(A-B)=(3)/(5) andtan Atan B=2, then cos A cos B=(1)/(5)(b)sin A sin B=-(2)/(5)cos A cos B=-(1)/(5)(d)sin A sin B=-(1)/(5)

If cos(A-B)=(3)/(5) and tan A tan B=2,thencos A cos B=(1)/(5) b.cot cos B=-(1)/(5)cs in As in B=-(1)/(5)ds in As in B=-(1)/(5)

Find the cube of : (i) 2 2/5 (ii) 3 1/4 (iii) 0. 3 (iv) 1. 5

If a * b=a^2+b^2, then the value of (4 * 5) * 3 is (i) (4^2+5^2)+3^2 (ii) (4+5)^2+3^2 (iii) 41^2+3^2 (iv) (4+5+3)^2

The value of cos phi is (i) (5)/(4) (ii) (5)/(3)( iii) (3)/(5) (iv) (4)/(5)

If cos(A-B)=3/5 and tanAtanB=2 then......................... A) cos A cos B=1/5 B) sin A sin B = -2/5 C) cos A cos B =-1/5 D) sin A sin B =-1/5