A spherical planet has uniform density `pi/2xx10^(4)kg//m^(3)`. Find out the minimum period for a satellite in a circular orbit around it in seconds (Use `G=20/3xx10^(-11) (N-m^(2))/(kg^(2))`).

A satellite revolves around a planet of mean density 4.38 xx 10^(3)kg//m^(3) , in an orbit close to its surface. Calculate the time period of the satellite. Take, G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

A rod of 1.5m length and uniform density 10^(4)kg//m^(3) is rotating at an angular velocity 400 rad//sec about its one end in a horizontal plane. Find out elongation in rod. Given y=2xx10^(11)N//m^(2)

A rod of 1.5m length and uniform density 10^(4)kg//m^(3) is rotating at an angular velocity 400 rad//sec about its one end in a horizontal plane. Find out elongation in rod. Given y=2xx10^(11)N//m^(2)

A satellite revolves in an orbit close to the surface of a planet of mean density 5.51 xx 10^(3) kg m^(-3) . Calculate the time period of satellite. Given G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

Two metal spheres are falling through a liquid of density 2xx10^(3)kg//m^(3) with the same uniform speed. The material density of sphere 1 and sphere 2 are 8xx10^(3)kg//m^(3) and 11xx10^(3)kg//m^(3) respectively. The ratio of their radii is :-

Two metal spheres are falling through a liquid of density 2xx10^(3)kg//m^(3) with the same uniform speed. The material density of sphere 1 and sphere 2 are 8xx10^(3)kg//m^(3) and 11xx10^(3)kg//m^(3) respectively. The ratio of their radii is :-

Two metal spheres are falling through a liquid of density 2xx10^(3)kg//m^(3) with the same uniform speed. The material density of sphere 1 and sphere 2 are 8xx10^(3)kg//m^(3) and 11xx10^(3)kg//m^(3) respectively. The ratio of their radii is :-

A uniform solid sphere has radius 0.2 m and density 8xx10^(3)kg//m^(2) . Fing the moment of inertia about the tangent to its surface. (pi=3.142)

Given Y = 2 xx 10^(11)N//m^(2), rho = 10^(4) kg//m^(3) Find out elongation in rod.