The displacement equation of a particle is `x=3 sin 2t+4cos2t`. The amplitude and maximum velocity will be respectively

The displacement eqution of a particle is x=3 sin 2t + 4 cos 2t . The amplitude and maximum velocity will be respetively

The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t . The amplitude and maximum velocity of a particle respectively are………….

The amplitude and maximum velocity will be respectively X= 3 sin 2t + 4 cos 2t The amplitude and maximum velocity will be respectively

The displacement xi in centimetres of a particle is xi = 3 sin 314 t + 4 cos 314 t . Amplitude and initial phase are

The displacement xi in centimetres of a particle is xi = 3 sin 314 t + 4 cos 314 t . Amplitude and initial phase are

The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

The displacement of a particle is given by x = 3 sin ( 5 pi t) + 4 cos ( 5 pi t) . The amplitude of particle is

The displacement of a SHM particle is y= 3 sin omega t+4 cos omega t then its amplitude will be……

If the displacement of a particle is given by y(t)=A sin (omega t +phi) , then find the maximum velocity of the particle.