The angle of a prism is `60^(@)` and its refractive index is `sqrt(2)`. The angle of minumum deviation sufferred by a ray of light in passing through it is

The angle of a prism is 60^(@) and its refractive index is sqrt2 . The angle of minimum deviation suffered by a ray of light in passing through it is

The refractive index of the material of a prism is sqrt((3)/(2)) and the refracting angle is 90^(@) The angle of minimum deviation of the refracted ray by the prism is

(a) If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then find the angle of incidence. (b) A ray of light passes through an equilateral prism such that the angle of emergence is equal to the angle of incidence and each is equal to 3//4^(th) of the angle of prism. Find the angle of deviation. (c) The refracting of a prism is A and the refractive index of the material of the prism is cotA//2 . Find the angle of deviation. (d) The angle of a prism is 60^@ . What is the angle of incidence for minimum deviation? The refractive index of the material of the prism is sqrt2 .

The angle of a prism is 6^(@) and its refractive index for green light is 1.5. If a green ray passes through it, the deviation will be

The angle of a prism is 6^@ and its refractive index for green light is 1.5 .If a green ray passes through it,the deviation will be

The angle of incidence for a ray of light at a refracting surface of a prism is 45^(@) . The angle of prism is 60^(@) . If the ray suffers minimum deviation through the prism. The angle of minimum deviation and refractive index of the material of the prism respectively, are