The locus of the point equidistant from two given points a and b is given by

Prove that the locus of the point equidistant from two given points is the straight line which bisects the line segment joining the given points at right angles.

The locus of a point equidistant from two intersecting lines is

The locus of a point equidistant from three collinear points is

Locus of the points equidistant from the point (-1, -1) and (4, 2) is

The equation of the locus of the points equidistant from the point A(-2,3) and B(6,-5) is

The locus of the point equidistant from (1,-1) and (-1,1) is

The locus of a point equidistant from two points with position vectors vec a and vec b is

The locus of the point (x,y) which is equidistant from the points (a + b, b -a ) and (a-b, a +b ) is :