If function f:R->R is defined by `f(x)=[x^2-a]/[x^2+a]` 0

The function f:R rarr R is defined by f(x)=3^(-x)

If the function f: R to R is defined by f(x)=x^(2)-6x-14 , then f^(-1)(2) is equal to -

The function f : R -> R is defined by f (x) = (x-1) (x-2) (x-3) is

The function f : R -> R is defined by f (x) = (x-1) (x-2) (x-3) is

Let f:R rarr R be a function is defined by f(x)=x^(2)-(x^(2))/(1+x^(2)), then

The function f:R rarr R is defined by f(x)=cos^(2)x+sin^(4)x for x in R. Then f(R) is

If R is the set of real numbers and a function f: R to R is defined as f(x)=x^(2), x in R , then prove that f is many-one into function.

The function f:R rarr R is defined by f(x)=(x-1)(x-2)(x-3) is