If `(2+iota)(2+2iota)(2+3iota).....(2+9iota)=x+iotay`, then 5.8.13.....85=

If (2+iota)(2+2 iota)(2+3 iota)......(2+9 iota)=x+iota y, then 5.8.13......85=

sqrt(5+12 iota)

The conjugate of (3-2iota)(2+3iota) is

Find the value of   ( iota^2 - iota ) times ( iota^2 + iota ) times ( iota^3 + iota ) is

Simplify: a.(4 iota^(3)-iota)/(2 iota+1) b.(sqrt(3)+iota)^(6)

The modulus value of (3-2t)(3+2 iota)(1+iota) is

If ((1+iota)^(2))/(2-iota)=x+iotay , then value of x+y will be a) 2/5   b)  -4/5 c)  -2/5 d) 4/5

The straight line (1+2 iota)z+(2 iota-1)bar(z)=10 iota on the complex plane,then the intercept on imaginary axis

Evaluate : (-5iota) times ( iota/8 ) is equal to

Value of (- iota ) ^(4/3)