In an isobaric process, the ratio of heat supplied to the system `(dQ)` and work done by the system `(dW)` for diatomic gas is

In an isobaric process of an ideal gas. The ratio of heat supplied annd work done by the system [i.e.,((Q)/(W))] is

In an isobaric process of an ideal gas. The ratio of heat supplied annd work done by the system [i.e.,((Q)/(W))] is

For an isobaric process,the ratio of Delta Q (amount of heat supplied) to the Delta (work done by the gas) is (gamma=(C_(P))/(C_(v)))

For a gaseous system find change in internal energy if the heat supplied to the system is 50 J and work done by the system is 16 J.

For a gaseous system find change in internal energy if the heat supplied to the system is 50 J and work done by the system is 16 J.

For a gaseous system find change in internal energy if the heat supplied to the system is 50 J and work done by the system is 16 J.

First law of thermodynamics is the general law of conservation of energy as applied to heat energy. According to this law, whenever heat is added to a system, it transforms to an equal amount of some other forms of energy. If dQ= a small amount of heat supplied to the system, dW= small amount of work done by the system and dU= small change in internal energy of the system, then dQ=dU+dW . Read the above passage and answer the following questions: (i) The amount of heat obsorbed by a gas is 10 cals and work done on the gas in 58J . Calculate increase in internal energy of the gas. (ii) What values of life do you learn fron this law?

For a gaseous state if heat supplied to the system is 100 J and work done by the system is 25 J. then internal energy of the system is

For a gaseous state if heat supplied to the system is 100 J and work done by the system is 25 J. then internal energy of the system is