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For certain curves y= f(x) satisfying `[d^2y]/[dx^2]= 6x-4`, f(x) has local minimum value 5 when x=1. 9. Number of critical point for y=f(x) for x € [0,2] (a) 0 (b)1. c).2 d) 3 10. Global minimum value y = f(x) for x € [0,2] is (a)5 (b)7 (c)8 d) 9 11 Global maximum value of y = f(x) for x € [0,2] is (a) 5 (b) 7 (c) 8 (d) 9

Text Solution

Verified by Experts

`d/dx(dy/dx)=6x-4`
`intd(dy/dx)=int(6x-4)*dx`
`dy/dx=3x^2-4x+c`
`f'(x)=dy/dx=3x^2-4x+c`
`f'(1)=0` and f(1)=5
3-4+c=0
c=1
`dy/dx=3x^2-4x+1`
...
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