`2x+3y=1` find the slope

Consider the curve 2y=3-x^2 Find the slope of the tangent to this curve at (x_1,y_1) .

Consider the function y=x^3-6x^2+3x-1 Find the slope at x=-1 .

Consider the curve x^(2/3)+y^(2/3)=2 Find the slope of the tangent to the curve at the point (1,1).

Reduce the following equations into slope intercept form and find their slopes and y intercepts. 2x+3y-7=0

Reduce the following into slope-intercept form and find their slopes and y-intercepts : 3x + 3y =5 .

Reduce the following equation into slope - intercept form and find their slopes and the y - intercepts.:- 6x + 3y -5 = 0

Reduce the following into slope-intercept form and find their slopes and y-intercepts : 7x +3y -6=0 .

Reduce the following into slope-intercept form and find their slopes and y-intercepts : 6x + 3y-5=0 .

Reduce the equation 2x-3y-5=0 to slope-intercept form, and find from it the slope and y-intercept