Calcualte the time required for the initial concentration of `2.0 mol//dm^(3)` to get reduced to `1.2 mol//dm^(3)`. Given specific rate constant(k) = `0.009 min^(-1)`

In a first order reaction, the concentration of reactant decreases from 0.8 mol/ dm^(3) to 0.05 mol/ dm^(3) in 2 xx 10^(4) sec. The rate constant in sec^(-1) is:

For a chemical raction AtoB the rate of the reaction is 2xx10^(-3) mol dm^(-3)s^(-1) , when the initial concentration is 0.05 mol dm^(-3) . The rate of the same reaction is 1.6xx10^(-2) mol dm^(-3)s^(-1) when the initial concentration is 0.1 mol dm^(-3) . The order of the reaction is

For a chemical reaction Ararr B ,the rate of the reaction is 2.0xx10^(-3) sec^(-1) , when the initial concentration is 0.05 mol dm^(-3) . The rate of the same reaction is 1.6xx10^(-2) mol dm^(-3) sec^(-1) . When the initial concentration is 0.1 mol dm^(3) , find the order of reaction.

In the first order reaction , the concentration of reactant decrease from 800 mol//dm^3 to 50 mol//dm^3 in 2 xx 10^4 sec . The rate constant for the reaction is

In a first order reaction the concentration of reactant decreases from 800 mol/dm to 50mol//dm^(3) in 2xx10^(2)s . The rate constant of reaction in s^(-1) is

In a first order reaction the concentration of reactant decreases from 800 mol/dm to 50mol//dm^(3) in 2xx10^(2)s . The rate constant of reaction in s^(-1) is