The angless of a triangle are in the proportion `7:2:1`, prove that the ratio of the least side to the greatest is `3-sqrt(5) : 2`.

The angle of a triangle are in the ratio 1 : 2 : 7, prove that the ratio of the greatest side to the least side is (sqrt(5)+1):(sqrt(5)-1) .

The angles of a triangle are in the ratio 3:5:10 . Then the ratio of the smallest side to the greatest side is

The angles of a triangle are in the ratio 3:5:10 .Then the ratio of the smallest side to the greatest side is

The angles of a triangle are in the ratio 3:5:10. Then the ratio of the smallest side to the greatest side is

If the angles of a triangle are in the ratio 7:2:1, then prove that the ratio of smallest side to the largest side is sqrt(5)-1:sqrt(5)+1

The angles of a triangle are in the ratio 3 : 5 : 10, the ratio of the smallest side to the greatest side is

The angles of a triangle are in the ratio 3 : 5 : 10, the ratio of the smallest side to the greatest side is

IF the angles of a triangle are in the ratio 2:3:5 , then the ratio of the greatest side to the least side is

If the angles of a triangle are in the ratio 4:1:1, then the ratio of the longest side to the perimeter is sqrt(3):(2+sqrt(3))( b) 1:61:2+sqrt(3)(d)2:3

If the angles of a triangle are in the ratio 4:1:1 then the ratio of the longest side to the perimeter is- sqrt(3):(2+sqrt(3)) b.1:sqrt(3)c1:2+sqrt(3)d.2:3