[" Calculate the force required to increase length by "1%" of a rod of area of cross-section "10^(-3)m^(2)" .Modulus of "],[" elasticity is "1.2times10^(12)Nm^(-2)" ."]

The force in newton required to increase by 1% length of a rod of area of cross section 10^(-3) m squre is …….., Modulus of elaticity of rod is 1.2 xx 10^(12) N m^(-2)

Calculate the force required to increase by 1% length of a rod of cross -sectional area 10^(-3) m [Y = 1.2*10^(12) Nm^2]

Calculate the force required to increase the length of a steel wire of cross- sectional area 10^(-6)m^(2) by 0.5% given: Y_(("for steel"))=2xx10^(11)N-m^(2)

Determine the force required to double the length of the steel wire of area of cross-section 5 xx 10^(-5) m^(2) . Give Y for steel = 2 xx 10^(11) Nm^(-2) .

Calculate the force required to incrase the length of wire of cross-sectional area 10^(-6) m^(2) by 50% if the Young's modulus of the material of the wire is 90 xx 10^(9) Pa .

Calculate the resistance of a metal wire of length 2 m and area of cross section 1·55 xx 10^(-6) m^(2) , if the resistivity of the metal be 2·8 xx 10^(-8) Omega m ?

There is some change in length when a 33000 N tensile force is applied on a steel rod of area of cross-section 10^(-3)m^(2) . The change of elongation of the steel rod when heated is (Y = 3 xx 10^(11)N // m^(2) , alpha = 1.1 xx 10^(-5 //@)C)

The workdone in increasing the length of a one metre long wire of cross - sectional area 1 m m^(2) through 1mm will be (Y=2xx10^(11)Nm^(-2)) :

The workdone in increasing the length of a one metre long wire of cross - sectional area 1 m m^(2) through 1mm will be (Y=2xx10^(11)Nm^(-2)) :

If young's modulus of steel is 2xx10^(11)N//m^(2) , then the force required to increase the length of a wire of cross section 1 cm^(2) by 1% will be