In a Young's double slit experiment `lamda= 500nm, d=1.0 mm andD=1.0m`. Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

In Young's double-slit experiment lambda = 500 nm, d = 1 mm , and D = 4 m . The minimum distance from the central maximum for which the intensity is half of the maximum intensity is '**' xx 10^(-4) m . What is the value of '**' ?

In Young's double-slit experiment lambda = 500 nm, d = 1 mm , and D = 4 m . The minimum distance from the central maximum for which the intensity is half of the maximum intensity is '**' xx 10^(-4) m . What is the value of '**' ?

In a Young's double-slit experiment, lambda=500nm . d=1nm and D=1m .The minimum distance from the central maximum,at which the intensity is half of the maximum intensity,is x times10^(-4)m .The value of x is(---) .

In a Young's double slit experiment,two slits are 1.5 mm apart and a screen in placed at a distance 1.2 m from the plane of the slits .The slits are illuminated with light of wavelength 6,000 overset @A .Find the inimum distance from the central maximum for which the intensity is half of the maximum intensity.

In Young's experiment the slits, separated by d = 0.8 mm , are illuminated with light of wavelength 7200 Å, Interference pattern is obtained on a screen D = 2 m from the slits. Find minimum distance from central maximum at which the a average intensity is 50% if of maximum?

In Young's experiment the slits, separated by d = 0.8 mm , are illuminated with light of wavelength 7200 Å, Interference pattern is obtained on a screen D = 2 m from the slits. Find minimum distance from central maximum at which the a average intensity is 50% if of maximum?

In a Young's double slit experiment, I_0 is the intensity at the central maximum and beta is the fringe width. The intensity at a point P distant x from the centre will be