The parametric equation of a parabola is `x=t^2+1,y=2t+1.` Then find the equation of the directrix.

The parametric equation of a parabola is x=t^2-1,y=3t+1. Then find the equation of the directrix.

The parametric equation of a parabola is x=t^2+1, y=2t+1 . The cartesian equation of its directrix is

The parametric equations of a parabola are x=t^2+1, y=2t+1. The Cartesian equation of its directrix is a. x=0 b. x+1=0 c. y=0 d. none of these

The parametric equation of the parabola are x=t^(2)+1,y=2t+1 The cartesian equation of the directrix is

The parametric equations of a parabola are x=t^(2)+1,y=2t+1. The Cartesian equation of its directrix is x=0 b.x+1=0 c.y=0 d.none of these

The parametric equations of the parabola y^(2) = 12x are _

t in R parametric equation of parabola are x=at^2 and y = 2at .

If y^(2)=-12x is the given equation of the parabola,then find the equation of the directrix.

If parametric representation of a parabola is x=2+t^(2) and y=2t+1 , then