`1.355 g` of a substance dissolved in `55 g`of `CH_(3)COOH` produced a depression in the freezing point of `0.618^(@)C`. Calculate the molecular weight of the substance `(K_(f)=3.85)`

2.71 g of a substance dissolved in 55 g of CH2COOH produced a depression in the freezing point of 0.618 o C. Calculate the molecular weight of the substance. (Kf=3.85)

6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

15 gm of a substance dissolved in 450 gms of water produces a depression of -0.34^@ C in the freezing point . Calulation the Mol. Wt. of the solid ( K_f for water is 1.86 K kg mol ^(-1) )

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 ^(@)C kg mol ^(-1))

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 K kg mol ^(-1))