If `bara,barb,bar c` are position vectors of the non- collinear points A, B, C respectively, the shortest distance of A from BC is

If veca,vecb,vec c are position vectors of the non- collinear points A, B, C respectively, the shortest distance of A from BC is

The position vectors of the three non-collinear points A, B, C, are bara, barb, barc respectively. The distance of the origin from the plane through A, B, C is

If bar(a),bar(b),bar(c) are the position vectors of the points A,B,C respectively such that 3bar(a)+5bar(b)=8bar(c) , the ratio in which A divides BC is

If bar(a), bar(b), bar(c) are the position vectors of the vertices A, B, C of the triangle ABC, then the equation of the median from A to BC is

If bara and barb are non-collinear vectors, then

If the position vectors of the points A,B,C are bara,barb and 3bara-2barb respectively, then the position A,B,C are

If the position vectors of the points A,B and C be a,b and 3a-2b respectively, then prove that the points A,B and C are collinear.

If the position vectors of the points A,B and C be a,b and 3a-2b respectively, then prove that the points A,B and C are collinear.

If the position vectors of the points A,B and C be a,b and 3a-2b respectively, then prove that the points A,B and C are collinear.

If the position vectors of the points A,B and C be a,b and 3a-2b respectively, then prove that the points A,B and C are collinear.