if the intensity of light is made `4I_0`, then the saturation current will become

In question 23, if the intensity of light is made 4 I, the saturation current will become

In the previous question, if the intensity of light is made 4I_0 , then the stopping potential will become

In the previous question, if the intensity of light is made 4I_0 , then the stopping potential will become

In the previous, if the intensity of light is made 4 I, the stopping potential will become

Given that a photon of light of wavelength 10,000Å has an energy equl to 1.23eV. When light of wavelength 5000Å and intensity I_(0) falls on a photoelectric cell and the saturation current is 0.40xx10^(-6) ampere and the stopping potential is 1.36 volt, then (i)what is the work function? (ii) If intensity of light is made 4I_(0) , what should be the saturation current and stopping potential?

Light of certain frequency and intensity incident on a photosensitive material causes photoelectric effect. If both the frequency and intensity are doubled, the photoelectric saturation current becomes

For intensity I of a light of wavelength 5000 Å the photoelectron saturation current is 0.40 mu A and stopping potential is 1.36 V , the work function of metal is

For intensity I of a light of wavelength 5000 Å the photoelectron saturation current is 0.40 mu A and stopping potential is 1.36 V , the work function of metal is