`A(z_1)`,`B(z_2)` and `C(z_3)` are the vertices of triangle ABC inscribed in the circle |z|=2,internal angle bisector of angle A meets the circumcircle again at `D(z_4)`.Point D is:

A(z_1),B(z_2),C(z_3) are the vertices a triangle ABC inscribed in the circle abs(z)=2 internal angle bosector of the angle A meet the circumference again at D(z_4) then prove z_4^2=z_2z_3

If A(z_1),B(z_2),C(z_3) and D(z_4) be the vertices of the square ABCD then

if z_1, z_2, z_3 are the vertices pf an equilateral triangle inscribed in the circle absz=1 and z_1=i , then

If z_(1),z_(2),z_(3) are vertices of an equilateral triangle inscribed in the circle |z|=2 and if z_(1)=1+iota sqrt(3), then

Let the complex numbers z_1, z_2 and z_3 represent the vertices A, B and C of a triangle ABC respectively, which is inscribed in the circle of radius unity and centre at origin.The internal bisector of the angle A meets the circumcircle again at the point D, Which is represented by the complex number z_4 and altitude from A to BC meets the circumcircle at E. given by z_5. Then arg([z_2z_3]/z_4^2) is equal to

lf z_1,z_2,z_3 are vertices of an equilateral triangle inscribed in the circle |z| = 2 and if z_1 = 1 + iotasqrt3 , then

If z_(1),z_(2),z_(3) are the vertices of an isoscles triangle right angled at z_(2) , then

If z_(1),z_(2),z_(3) are the vertices of an isoscles triangle right angled at z_(2) , then