if `veca=2vecm+vecn` and `vecb=vecm-2vecn` angle between the `vecm & vecn`is `60^@ , a,b` are side of the parallogram then length of the diagonals :

If 2veca*vecb = |veca| * |vecb| then the angle between veca & vecb is

If 2(veca.vecb)= |veca||vecb| then angle between veca and vecb equals to ,

If |\veca|=sqrt3,|\vecb|=2 and angle between veca and vecb is 60^o . Find veca.vecb .

If |vecA+vecB|=|vecA|=|vecB| then angle between A and B will be

If |vecA+vecB|=|vecA|=|vecB| then angle between A and B will be

Let veca and vecb be two vectors such that |2 veca + 3 vecb| = |3 veca + vecb| and the angle between veca and vecb is 60^(@) . If 1/8 veca is a unit vector, then |vecb| is equal to :

The vector veca=3hati-2hatj+2hatk and vecb=-hati-2hatk are the adjacent sides of a parallelogram. The acute angle between its diagonals is ……….

If veca=a_1 vecl+a_2 vecm+a_3vecn, vecb=b_1 vecl+b_2vecm+b_3vecn and vecc=c_1 vecl+v_2vecm+c_3 vecn where vecl,vecm,vecn are three non coplnar vectors then show that [veca vecb vecc]=|(a_1,a_2,a_3),(b_1,b_2,b_3),(c_1,c_2,c_3)|[vecl vecm vecn]