" (iv) "[(2x)/(a)+(y)/(b)=2],[(x)/(a)-(y)/(b)=4,a!=0,b!=0]

(x)/(a)+(y)/(b)=a+b(x)/(a^(2))+(y)/(b^(2))=2,a!=0,b!=0

2(a x-b y)+(a+4b)=0 , 2(b x+a y)+(b-4a)=0

Solution to (a^2)/(x)-(b^2)/(y)=0, (a^2b)/(x)+(b^2a)/(y)=a+b,x ne0,y ne0 is………

Solve the following pair of equations for x and y : (a^(2))/(x)-(b^(2))/(y)=0, (a^(2)b)/(x)+(b^(2)a)/(y)=a+b , x ne 0 , y ne 0 .

(a)/(x)-(b)/(y)=0,(ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2)

Solve : {:((a)/(x)-(b)/(y)=0),((ab^(2))/(x)+(a^(2)b)/(y)=a^(2)+b^(2)):}

Solve the following system of equations by method of cross-multiplication: (a^(2))/(x)-(b^(2))/(y)=0,quad (a^(2)b)/(x)+(b^(2)a)/(y)=a+b,quad x,y!=0

x/a-y/b=0 , a x+b y=a^2+b^2

{:((a^(2))/(x) - (b^(2))/(y) = 0),((a^(2)b)/(x)+(b^(2)a)/(y) = "a + b, where x, y"ne 0.):}