The point of application of the force (-2,4,7) is displaced from the point (3,-5,1) to the point (5,9,7) .But the force is suddenly halved when the point of application moves half the

Point Of Application Of Force

The distance from the point (7,1,a) to the point (4,5,9) is 5. Find the value of a.

A particie is displaced from the point (2,1,-1) to the point (4,3,-4) by the force 2 hati = 4 hatj - 5 k. Then the work done by the force is

A force vecF=hat i+5 hat j+7 hat k acts on a particle and displaces it throught vec s=6 hat I +9 hat k . Calculate the work done if the force is in newton and displacement in metre. (ii) Find the work done by force vec F=2hat i-3 hat j+hatk when its point of application moves from the point A(1,2,-3) to the point B (2,0, -5).

If a particle moves from the point A(1 , 2 , 3) to the point B( 4 , 6 ,9) , its displacement vector be

If a particle moves from the point A(1 , 2 , 3) to the point B( 4 , 6 ,9) , its displacement vector be

A particle being acted upon by the forces 5hat(i)-2hat(j)+hat(k) and 3hat(i)+hat(j)-2hat(k) is displaced from the point (2,3,5) to the point (7,-2,4) . The work done by the forces is equal to