If `A+C=2B, then (cosC-cosA)/(sinA-sinC)=`

If A+B+C=pi , prove that : (cosA)/(sinBsinC) + (cosB)/(sinC sinA) + (cosC)/(sinA sinB) =2 .

If A+B+C=pi , prove that (cosA)/(sin B sinC)+(cos B)/(sin C sinA)+(cos C)/(sin A sinB)=2 .

If A+B+C=pi , prove that : (cosA)/(sinb sinC) + (cosB)/(sinC sin) + (cosC)/(sinA sinB) =2 .

If A+B+C=pi , prove that : (cosA)/(sinb sinC) + (cosB)/(sinC sin) + (cosC)/(sinA sinB) =2 .

In triangle ABC , right angled at B, if tanA =1/2 , then the value of (sinA(cosC + cosA))/(cosC(sinC - sinA)) is: triangle ABC में B एक समकोण है यदि tanA =1/2 तो (sinA(cosC + cosA)) /(cosC(sinC - sinA)) का मान क्या होगा ?

If A+B+C=pi , prove that : cosA sinB sinC +cosB sinC sinA+cosC sinA sinB=1+cosA cosB cosC .

If A+B+C=pi , prove that : cosA sinB sinC +cosB sinC sinA+cosC sinA sinB=1+cosA cosB cosC .

If A+B+C= pi and cosA+cosB+cosC=0=sinA+sinB+sinC then cos3A+cos3B+cos3C=

|[sin^2A, sinA, cos^2A] , [sin^2B, sinB, cos^2B] , [sin^2C, sinC, cos^2C]|=-(sinA-sinB)(sinB-sinC)(sinC-sinA)

In triangleABC, a(sinB-sinC)+b(sinC-sinA)+c(sinA-sinB)=