If the area of the triangle formed formed `z`, `wz` and `z=wz` where `w` is the cube root of unity is `16sqrt3 `sq units then `|z|=`

Explanation

Please refer to video to see the diagram.

As `omega` is the cube root of unity,

So, angle between `omega` and `omegaz` will be `120^@`.

As, sum of two vertices of the traingles `omega` and `omegaz` is equal to `omega+omegaz`,

so, the quadrilateral in the diagram is a parallelogram.

So, the remaining angles of the traingle will be `30^@`.

Now, area of the triangle, `A = 1/2*b*h`

`16sqrt3 = 1/2**2|z|cos30^@**|z|sin30^@`

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