A radioactive sample has `N_0` active at `t = 0` . If the rate of disintegration at any time is `R` and the number of atoms is `N`, them the ratio `R//N` varies with time as.

The rate of disintegration of a radioactive substance is …………………………… to the number of atoms present at that time .

The rate of disintegration of a radioactive substance is …………………………… to the number of atoms present at that time .

The radioactive of a sample is R_(1) at a time T_(1) and R_(2) at a time T_(2) . If the half-life of the specimen is T , the number of atoms that have disintegrated in the time (T_(2)-T_(1)) is equal to (n(R_(1)-R_(2))T)/(ln4) . Here n is some integral number. What is the value of n?

The radioactive of a sample is R_(1) at a time T_(1) and R_(2) at a time T_(2) . If the half-life of the specimen is T , the number of atoms that have disintegrated in the time (T_(2)-T_(1)) is equal to (n(R_(1)-R_(2))T)/(ln4) . Here n is some integral number. What is the value of n?

The radioactivity of a sample is R_(1) at a time T_(1) and R_(2) at time T_(2) . If the half-life of the specimen is T, the number of atoms that have disintegrated in the time (T_(2) -T_(1)) is proporational to

The radioactivity of a sample is R_(1) at a time T_(1) and R_(2) at time T_(2) . If the half-life of the specimen is T, the number of atoms that have disintegrated in the time (T_(2) -T_(1)) is proporational to

The radioactivity of sample is R_(1) at a time T_(1) and R_(2) at a time T_(2) . If the half -life of thespeciman is T, the number of atoms that have disintegrated in the time (T_(2)-T_(1)) is equal to :

The radioactivity of a sample is R_(1) at a time T_(1) and R_(2) at time T_(2) . If the half-life of the specimen is T, the number of atoms that have disintegrated in the time (T_(2) -T_(1)) is proporational to