If .^(20)C(1)+(2^(2)) .^(20)C(2) + (3^(2...

If `.^(20)C_(1)+(2^(2)) .^(20)C_(2) + (3^(2)).^(20)C_(3) +......+(20^(2)).^(20)C_(20)=A(2^(beta))` , then the ordered pair `(A, beta)` is equal to

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The value of 1^(1).^(20)C_(1)+2^(2).^(20)C_(2)+3^(2).^(20)C_(3)+….+(20)^(2).^(20)C_(20) is

1.^(20)C_(1)-2.^(20)C_(2)+3.^(20)C_(3)-...-20.^(20)C_(20)

Find the value of .^(20)C_(0) - .^(20)C_(1)+ .^(20)C_(2) - .^(20)C_(3) +"……"-"....." + .^(20)C_(10) . is

The sum of the series .^(20)C_(0)-.^(20)C_(1)+ .^(20)C_(2)-.^(20)C_(3)+...-.+ .^(20)C_(10) is -

""^(20)C_(0)-(""^(20)C_(1))/(2)+(""^(20)C_(2))/(3)-(""^(20)C_(3))/(4)+....

The sum of the series 20C_(0)-^(20)C_(1)+^(20)C_(2)-^(20)C_(3)+...-...+^(20)C_(10) is:

let 2..^(20)C_(0)+5.^(20)C_(1)+8.^(20)C_(2)+?.+62.^(20)C_(20) . Then sum of this series is