The x-z plane separates two media A and B of refractive indices `mu_(1) = 1.5` and `mu_(2) = 2`. A ray of light travels from A to B. Its directions in the two media are given by unit vectors `u_(1) = a hat(i)+b hat(j)` and `u_(2) = c hat(i) +a hat(j)`. Then

The x-z plane separates two media A and B of refractive indices mu_(1)=1.5 and mu_(2)=2 . A ray of light travels from A to B its direction in the two media are given by unit vectors vec(u)_(1)=a hat(i) + b hat(j) and vec(u)_(2)= chat(i)+dhat(j) Then

The xz plane separates two media A and B with refractive indices mu_(1) & mu_(2) respectively. A ray of light travels from A to B . Its directions in the two media are given by the unit vectors, vec(r)_(A)=a hat i+ b hat j & vec(r)_(B)= alpha hat i + beta hat j respectively where hat i & hat j are unit vectors in the x & y directions. Then :

The xz plane separates two media A and B with refractive indices mu_(1) & mu_(2) respectively. A ray of light travels from A to B . Its directions in the two media are given by the unut vectors, vec(r)_(A)=a hat i+ b hat j & vec(r)_(B) alpha hat i + beta hat j respectively where hat i & hat j are unit vectors in the x & y directions. Then :

The xz plane separates two media A and B with refractive indices mu_(1) & mu_(2) respectively. A ray of light travels from A to B . Its directions in the two media are given by the unut vectors, vec(r)_(A)=a hat i+ b hat j & vec(r)_(B) alpha hat i + beta hat j respectively where hat i & hat j are unit vectors in the x & y directions. Then :

Speed of light through two media of refractive indices mu_(1) and mu_(2) are u_(1) and u_(2) respectively, then

What are the resultants of the vector product of two given vectors given by vec(A) = 4 hat(i) - 2 hat(j) + hat(k) and brc(B) = 5 hat(i) + hat(j) - 4 hat(k) ?

Find a unit vector perpendicular to the plane of two vectors a=hat(i)-hat(j)+2hat(k) and b=2hat(i)+3hat(j)-hat(k) .