In the diagram as shown, a circle is drawn with centre C(1, 1) and radius I and a line L. The line Lis tangential to the circle at Q. Further L meet the y-axis at R and the x-axis at Pis such a way that the angle OPQ equals `theta` where `0 < theta

In the diagram as shown, a circle is drawn with centre C(1,1) and radius 1 and a line L. The line L is tangent to the circle at Q. Further L meets the y-axis at R and the x-axis at P in such a way that the angle OPQ equals theta where 0 lt theta lt (pi)/(2) . Coordinate of Q is

In the diagram as shown, a circle is drawn with centre C(1,1) and radius 1 and a line L. The line L is tangent to the circle at Q. Further L meets the y-axis at R and the x-axis at P in such a way that the angle OPQ equals theta where 0 lt theta lt (pi)/(2) . Area of triangle OPR when theta = pi//4 is

In the diagram as shown, a circle is drawn with centre C(1,1) and radius 1 and a line L. The line L is tangent to the circle at Q. Further L meets the y-axis at R and the x-axis at P in such a way that the angle OPQ equals theta where 0 lt theta lt (pi)/(2) . Equation of the line PR is

In the diagram as shown, a circle is drawn with centre C(1,1) and radius 1 and a line L. The line L is tangent to the circle at Q. Further L meets the y-axis at R and the x-axis at P in such a way that the angle OPQ equals theta where 0 lt theta lt (pi)/(2) . Equation of the line PR is

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4 The radius of the circle is:

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y=4. The radius of the circle is :

A circle touches y-axis at (0, 5) and whose centre lies on the line 2x + y = 13, find the equation of the circle.

The line l in Fig14.14 meets X-axis at A(-5,0) and Y-axis at B(0,-3).